%This command provides the additional trigonometric functions %displayed in the column three of the page 4 % %The command has one parameter: % 1) The width of the text \newcommand\TFourTrigTwo[1]{% \parbox[t]{#1}{% \deflength\TmpLengthA{3ex plus .5ex minus 1.5ex} \DisplaySpace{\TFourDisplaySpace}{\TFourDisplayShortSpace} %Since the width of the column is narrow, ragged right %looks better \raggedright \input{triangle.tex} \usebox\TriangleBox \TFourTitle{Law of cosines:} \begin{DisplayFormulae}{1}{0pt}{\TmpLengthA}{\BigChar}{\StyleWithoutNumber} \def\FirstPart{c^2 = \mbox{}} \FmPartA{\FirstPart a^2 + b^2 -}. \FmPartB{\FirstPart}{2ab \cos C}. \end{DisplayFormulae} \TFourTitle{Area:} \AdjustSpace{-2.5ex plus .5ex minus .5ex} \begin{DisplayFormulae}{1}{0pt}{1.1\TmpLengthA}{\BigChar}{\StyleWithoutNumber} \def\FirstPart{A} \FmPartA{\FirstPart = \tfrac{1}{2} h c = \tfrac{1}{2} a b \sin C} \FmPartB{\FirstPart}{= \tfrac{c^2 \sin A \sin B}{2 \sin C}} \end{DisplayFormulae} \TFourTitle{Heron's formula:} \begin{DisplayFormulae}{1}{0pt}{.9\TmpLengthA}{\BigChar}{\StyleWithoutNumber} \Fm{A = \sqrt{s \cdot s_a \cdot s_b \cdot s_c}} \Fm{s = \tfrac{1}{2} (a + b + c)} \Fm{s_a = s - a} \Fm{s_b = s - b} \Fm{s_c = s - c} \end{DisplayFormulae} \TFourTitle{More identities:} \begin{DisplayFormulae}{1}{0pt}{\TmpLengthA}{\BigChar}{\StyleWithoutNumber} \def\FmSep{\unskip\text{,}}%Comma is the separator of equation \Fm{\sin \tfrac{x}{2} = \sqrt{\dfrac{1 - \cos x}{2}}} \Fm{\cos \tfrac{x}{2} = \sqrt{\dfrac{1 + \cos x}{2}}} \def\FirstPart{\tan \tfrac{x}{2}}% \FmPartA{\FirstPart = \sqrt{\dfrac{1 - \cos x}{1 + \cos x}}} \FmPartB{\FirstPart}{\!= \dfrac{1 - \cos x}{\sin x}} \FmPartB{\FirstPart}{\!= \dfrac{\sin x}{1 + \cos x}} \def\FirstPart{\cot \tfrac{x}{2}} \FmPartA{\FirstPart = \sqrt{\dfrac{1 + \cos x}{1 - \cos x}}} \FmPartB{\FirstPart}{\!=\dfrac{1 + \cos x}{\sin x}} \FmPartB{\FirstPart}{\!=\dfrac{\sin x}{1 - \cos x}} \Fm{\sin x = \dfrac{e^{ix} - e^{-ix}}{2 i}} \Fm{\cos x = \dfrac{e^{ix} + e^{-ix}}{2}} \def\FirstPart{\tan x} \FmPartA{\FirstPart = -i \dfrac{e^{ix} - e^{-ix}}{e^{ix} + e^{-ix}}} \FmPartB{\FirstPart}{\!=-i \dfrac{e^{2ix} - 1}{e^{2ix} + 1}} \Fm{\sin x = \dfrac{\sinh i x}{i}} \Fm{\cos x = \cosh i x} \def\FmSep{\unskip\text{.}} \Fm{\tan x = \dfrac{\tanh i x}{i}} \end{DisplayFormulae} }% }